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Mathematics
If two numbers are in the ratio 1 / 3: 1 / 2, then by what percentage is the second number more than the first?
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Q. If two numbers are in the ratio $1 / 3: 1 / 2$, then by what percentage is the second number more than the first?
Percentages
A
$50 \%$
B
$37 \frac{1}{2} \%$
C
$33 \frac{1}{3} \%$
D
$40 \%$
Solution:
$2: 3 \Rightarrow$ Percentage more $=[\frac{(3-2)}{2}] \times 100=50 \%$