Since the angle of inclination $\theta=60^{\circ}$
$\therefore n=\frac{360^{\circ}}{60^{\circ}}=6$ which is even
$\therefore $ no. of images formed for any position of the object in between the mirrors $= 6 - 1 = 5 $
$\left(n\right)=\frac{360^{\circ}}{\theta}-1$
$ \Rightarrow \frac{360^{\circ}}{60}-1$
$ \Rightarrow 6-1$
$ \Rightarrow 5$