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Q.
If two dice are rolled together, what is the probability that the total score on the two dice is greater than 8 ?
Probaility
Solution:
$P($ greater than 8$)=P($ sum be 9$)+P($ sum be $10)+P($ sum be 11$)+P($ sum be 12$)$
Possible combinations are $(4,5),(5,4),(5,5)$, $(6,5),(5,6),(6,6)$
Possible outcomes $=6$
Total outcomes $=6 \times 6=36$
Hence, $P($ greater than 8$)=\frac{6}{36}=\frac{1}{6}$