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Q. If three particles of masses 2kg, 1kg and 3 kg are placed at comers of an equilateral triangle of perimeter 6m then the distance of center of mass which is at origin of particles from 1kg mass is (approximately) (Assume 2kg on x-axis )

Solution:

Co-ordinates o f 1 kg, 2 kg, 3 kg are (0,0), (2,0), (1, $\sqrt{3}$ ) respectively
$X_{cm} = \frac{\sum m_i x_i}{\sum m_i} ; Y_{cm} = \frac{\sum m_i y_i}{\sum m_i} r_{cm} = \sqrt{X^2_{cm} + Y^2_{cm}}$