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Q. If three capacitors each of capacity $1\, \mu F$ are connected in such a way that the resultant capacity is $1.5\, \mu F$, then

Electrostatic Potential and Capacitance

Solution:

The circuit can be drawn as follows
image
$\Rightarrow $ Equivalent capacitance
$C_{e q}=\frac{1}{2}+1=\frac{3}{2} \mu F$