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Q. If $ \theta ={{\sin }^{-1}}[\sin (-600{}^\circ )], $ then one of the possible values of $ \theta $ is:

KEAMKEAM 2002

Solution:

$ \theta ={{\sin }^{-1}}\{-\sin 600{}^\circ \}={{\sin }^{-1}}\{-\sin 240{}^\circ \} $ $ ={{\sin }^{-1}}\left( \frac{\sqrt{3}}{2} \right) $ $ \Rightarrow $ $ \theta =60{}^\circ =\frac{\pi }{3} $