Q. If $\theta_1, \theta_2$ and $\theta_3$ are the three values of $\theta \in[0,2 \pi]$ for which $\tan \theta=\lambda$ then the value of $\tan \frac{\theta_1}{3} \tan \frac{\theta_2}{3}+\tan \frac{\theta_2}{3} \tan \frac{\theta_3}{3}+\tan \frac{\theta_3}{3} \tan \frac{\theta_1}{3}$ is equal to ( $\lambda$ is a constant)
Trigonometric Functions
Solution: