Question

If there is no torsion in the suspension thread, then the time period of a magnet executing $SHM$ is

• A. $T=\frac{1}{2\pi} \sqrt { \frac{MB}{I}}$
• B. $T=\frac{1}{2\pi} \sqrt { \frac{I}{MB}}$
• C. $T=2\pi \sqrt { \frac{I}{MB}}$
• D. $T=2\pi \sqrt { \frac{MB}{I}}$

Answer 1

Answer: (C)

If there is no torsion in the suspension thread, then the time period of a magnet executing SHM is $T=2 \pi \sqrt{\frac{I}{M B}}$ where, $I$ is moment of inertia of short bar magnet, $B$ is Earth's magnetic field and $M$ is magnetic moment.