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Q.
If the wire has resistivity $\rho$ per unit area of cross-section, the resistance between $A$ and $B$ is
Current Electricity
Solution:
The figure can be redrawn as:
$R=\frac{\rho l}{2}$
$R_{1}=\frac{\rho l}{\sqrt{2}}$
$R_{ eq }=\frac{1}{2}\left[\frac{2 R R_{1}}{2 R+R_{1}}+2 R\right]=\frac{\rho l}{\sqrt{2}}$
