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Q. If the wavelength of the electromagnetic radiation is increased to thrice the digital value, then what will be the percent change in the value of frequency of the electromagnetic radiation.

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Solution:

$ v_1=\frac{c}{\lambda_1} $
$v_2=\frac{c}{\lambda_2}=\frac{c}{3 \lambda_1}$
$\%$ change in frequency $=\frac{v_2-v_1}{v_1} \times 100$
$=\frac{\frac{c}{3 \lambda_1}-\frac{c}{\lambda_1}}{\frac{c}{\lambda_1}} \times 100=\frac{-\frac{2 c}{3 \lambda_1} \times 100}{\frac{c}{\lambda_1}}=-66 \%$