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Q.
If the volume of the vessel in which the reaction $2 NO + O _{2} \longrightarrow 2 NO _{2}$, is occurring is diminished to $1 / 3 r d$ of its initial volume. The rate of the reaction will be increased by
As we know Aat, rate of reaction is directly proportional to concentration of reactant and inversely proportional to the volume of vessel.
ie, concentration $\propto \frac{n}{V}$
For a given reaction,
$2 NO (g)+ O _{2}(g) \rightleftharpoons 2 NO _{2}(g)$
Rate of reaction $=k[ NO ]^{2}\left[ O _{2}\right]$
If volume of vessel is reduced by $\frac{1}{3}$ rd of its initial value, then concentration of compound is increased by $3$ times. Hence, the rate of reaction will be increased by $27$ times.