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  4. If the voltage and current are given by V=(50± 4)V and I=(20± 0.4) text A, respectively, the percentage error in the resistance of conductor is

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Q. If the voltage and current are given by $ V=(50\pm 4)V $ and $ I=(20\pm 0.4)\text{ }A, $ respectively, the percentage error in the resistance of conductor is

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Solution:

Given, $ V=\left( 50\pm 4 \right)V $ $ I=\left( 20\pm 0.4 \right)\,A $ Now, from Ohms law, $ V=IR $ $ \therefore $ $ R=\frac{V}{I} $ Maximum percentage error in resistance i.e., $ \frac{\Delta R}{R}\times 100=\left( \frac{\Delta V}{V}\times 100 \right)+\left( \frac{\Delta I}{I}\times 100 \right) $ $ =\frac{4}{50}\times 100+\frac{0.4}{20}\times 100 $ $ =8+2=10% $