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  4. If the vertex of the parabola y = x2 - 16x + K lies on x-axis, then the value of K is

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Q. If the vertex of the parabola $y = x^{2} - 16x + K$ lies on $x$-axis, then the value of $K$ is

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Solution:

$y = x^{2} - 16x + K$
$\Rightarrow \, y=\left(x-8\right)^{2}+\left(K-64\right)$
Since vertex lies on $x$-axis
$\Rightarrow y=0$
$\left(x - 8\right)^{2} + \left(K - 64\right) = 0$
It can be possible only when $x = 8$ and $K = 64$.