1. Tardigrade
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  4. If the velocity of an electron moving in first Bohr's orbit of hydrogen has to be reduced to 7.27 × 105 m / s , it should be shifted by

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Q. If the velocity of an electron moving in first Bohr's orbit of hydrogen has to be reduced to $7.27 \times 10^{5} m / s ,$ it should be shifted by

Structure of Atom

Solution:

$7.27 \times 10^{5} \,m / s$ is the velocity of electron in the third Bohr's orbit of hydrogen atom. It means the electron has to be sent to the third shell. $r_{n}=0.529 n^{2} \, \mathring{A} $ for hydrogen.

Therefore, the distance through which an electron has to be shifted away from the nucleus $=r_{3}-r_{1}$.

$=\left[0.529 \times(3)^{2}-0.529 \times(1)^{2}\right] \mathring{A} =4.23 \, \mathring{A} $