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Physics
If the value of potential in an AC circuit is 10 V, then the peak value of potential is
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Q. If the value of potential in an AC circuit is $10 \,V$, then the peak value of potential is
Alternating Current
A
$\frac{10}{\sqrt{2}} V$
B
$10 \sqrt{2} V$
C
$20 \sqrt{2} V$
D
$\frac{20}{\sqrt{2}} V$
Solution:
$V_{0}=\sqrt{2} V_{ rms }=10 \sqrt{2} V$