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Q. If the unit of velocity is run, the unit of time is second and unit of force is strength in a hypothetical system of unit. In this system of unit, the unit of mass is (strength)$^{x}$ (second)$^{y}$ (run)$^{z}$ Find the value of $\frac{y}{x}$

Physical World, Units and Measurements

Solution:

$\because F=ma$
$\Rightarrow m=\frac{F}{\alpha}=\left(\text{Force}\right)/\frac{\text{Change in velocity}}{\text{Time}}$
$=\frac{\text{Force $\times$ Time}}{\text{Change in velocity}}$
=(strength)(s)(run) $^{-1}$
Thus, $x=1, y=1$ and $z=-1$
$\therefore \frac{y}{x}=1$