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Physics
If the temperatures of source and sink of a Carnot engine having efficiency n are each decreased by 100 K, then the efficiency
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Q. If the temperatures of source and sink of a Carnot engine having efficiency n are each decreased by 100 K, then the efficiency
KEAM
KEAM 2013
A
remains constant
B
becomes 1
C
decreases
D
increases
E
becomes zero
Solution:
In starting the efficiency
$\eta=1-\frac{T_{2}}{T_{1}}=\frac{T_{1}-T_{2}}{T_{1}}$
On decreased by $100 \,K$ each the efficiency
$\eta'=1-\frac{T_{2}-100}{T_{1}-100}=\frac{T_{1}-T_{2}}{T_{1}-100}$
In this case the etticiency will increases.