1. Tardigrade
  2. Question
  3. Chemistry
  4. If the standard electrode potential for a cell is 2 V at 300 K, the equilibrium constant (K) for the reaction Zn(s) + cu2+ (aq) <=> Zn2+ (aq) + Cu(s) at 300 K is approximately. (R = 8 JK-1 mol-1 , F = 96000 C mol-1)

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. If the standard electrode potential for a cell is 2 V at 300 K, the equilibrium constant (K) for the reaction
$\ce{Zn(s) + cu^{2+} (aq) <=> Zn^{2+} (aq) + Cu(s)}$ at 300 K is approximately.
$\ce{(R = 8 \; JK^{-1} \; mol^{-1} , F = 96000 \; C \; mol^{-1})}$

JEE MainJEE Main 2019Equilibrium

Solution:

$\ce{\Delta G^{\circ} = - RT \; lnk = - \; nFE^{\circ}_{cell}}$
$\ce{Ink = \frac{ n \times F \times E^{\circ}}{R \times T} = \frac{2 \times 96000 \times 2}{8 \times 300}} $
Ink = 160
$k = e^{160}$