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Q.
If the relation $R : A \to B$. where $A = \{1.2.3.4\}$ and $B = \{1.3.5\} $ is defined by $R = \{(x.y): x < y.x \in A,y \in B\}$ , then $R 0 R^{-1}$ is
Relations and Functions - Part 2
Solution:
Since $R = \begin{Bmatrix}\left(1.3\right)&\left(1.5\right)&\left(2.3\right)\\ \left(2.5\right)&\left(3.5\right)&\left(4.5\right)\end{Bmatrix} $ and
$R^{-1} = \begin{Bmatrix}\left(3.1\right)&\left(5.1\right)&\left(3.2\right)\\ \left(5.2\right)&\left(5.3\right)&\left(5.4\right)\end{Bmatrix}$
Thus, $ R0R^{-1} = \begin{Bmatrix}\left(3.5\right)&\left(5.5\right)\\ \left(3.3\right)&\left(5.3\right)\end{Bmatrix}$