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Q. If the red light is replaced by blue light illuminating the object in a microscope the resolving power of the microscope

Punjab PMETPunjab PMET 2010Ray Optics and Optical Instruments

Solution:

Resolvmg power $ = \frac{2 \mu\, \sin\, \theta}{1.22 \lambda}$
Since, $\lambda_R > \lambda_B$ hence, resolving power increases.