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Q. If the rate of increase of the radius of a circle is $5 \,cm/s$, then the rate of increase of its area, when the radius is $20\, cm$, will be

WBJEEWBJEE 2009Application of Derivatives

Solution:

Since, area of circle, $A=\pi r^{2}$

On differentiating w.r.t. t, we get

$\frac{dA}{dt}=2\pi r \frac{dr}{dt}$

$=2\pi\cdot20\cdot5=200\pi$