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Mathematics
If the rate of increase of the radius of a circle is 5 cm/s, then the rate of increase of its area, when the radius is 20 cm, will be
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Q. If the rate of increase of the radius of a circle is $5 \,cm/s$, then the rate of increase of its area, when the radius is $20\, cm$, will be
WBJEE
WBJEE 2009
Application of Derivatives
A
$10\,\pi$
10%
B
$20\,\pi$
11%
C
$200 \,\pi$
70%
D
$400 \,\pi$
9%
Solution:
Since, area of circle, $A=\pi r^{2}$
On differentiating w.r.t. t, we get
$\frac{dA}{dt}=2\pi r \frac{dr}{dt}$
$=2\pi\cdot20\cdot5=200\pi$