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Q. If the rate constant for a first order reaction is $k$, the time $(t)$ required for the completion of $99 \%$ of the reaction is given by

KCETKCET 2021Chemical Kinetics

Solution:

$t =\frac{2.303}{ k } \log \frac{100}{1}$
$=\frac{2.303}{ k } \times 2$
$t =\frac{4.606}{ k }$