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Q. If the radius of first Bohr orbit be $a_0$, then the radius of the third orbit would be -

Structure of Atom

Solution:

$r=0.529 \frac{n^{2}}{Z}\mathring{A}$
$n=1$,
$Z=1$
so $r = 0.529 \mathring{A}=a_{o} $
Therefore for third orbit
$r=0.529 \times9$
$ or\,\,\,\, r=9\times a_{o}$