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Q. If the radius of an octahedral void is $r$ and radius of atoms in close packing is $R$, the relation between $r$ and $R$ is

The Solid State

Solution:

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$\left(2R\right)^{2}=\left(R+r\right)^{2}+\left(R+r\right)^{2}$
$\sqrt{2}\,R=R+r$
$\left(\sqrt{2}-1\right)R=r$
$0.414R=r$