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Chemistry
If the radius of 2nd Bohr orbit of hydrogen atom is r2 The radius of third Bohr orbit will be
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Q. If the radius of $2^{nd}$ Bohr orbit of hydrogen atom is $r_{2}$ The radius of third Bohr orbit will be
Structure of Atom
A
$\frac{4}{9}r_{2}$
19%
B
$4r_{2}$
19%
C
$\frac{9}{4}r_{2}$
48%
D
$9r_{2}$
15%
Solution:
$r=\frac{n^{2} h^{2}}{4\pi^2 mZe^{2}}$
$ \therefore \frac{r_{2}}{r_{3}}=\frac{2^{2}}{3^{2}}$
$\therefore r_{3} =\frac{9}{4} r_{2} $