Let five consecutive terms of GP are $\frac{a}{r^{2}}, \frac{a}{r}, a, a r, a r^{2}$.
According to the question,
$\frac{a}{r^{2}} \times \frac{a}{r} \times a \times a r \times a r^{2}=\frac{243}{32} \Rightarrow a^{5}=\left(\frac{3}{2}\right)^{5}$
$\therefore a=\frac{3}{2}$, which is the middle term.