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Q. If the pressure and the volume of certain quantity of ideal gas are halved, then its temperature

KEAMKEAM 2012Kinetic Theory

Solution:

Ideal gas equal
$p V=\mu R T$
If pressure and the volume of certain quantity of ideal gas are halved
$\frac{p}{2} \times \frac{V}{2}=\mu R_{0} T_{1}$
$\frac{p V}{4} =\mu R T_{1} (\because R$ is constant $)$
$\frac{\mu R T}{4} =\mu R T_{1} $
$T_{1} =\frac{T}{4}$
In this condition, temperature becomes one-fourth.