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  4. If the potential barrier across a p-n junction is 0.6 V. Then the electric field intensity, in the depletion region having the width of 6 × 10-6 m, will be × 105 N / C.

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Q. If the potential barrier across a p-n junction is $0.6 V$. Then the electric field intensity, in the depletion region having the width of $6 \times 10^{-6} m$, will be ____ $\times 10^5 N / C$.

JEE MainJEE Main 2022Semiconductor Electronics: Materials Devices and Simple Circuits

Solution:

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$ E =\frac{ V }{ d }=\frac{\text { Potential barrier Across Junction }}{\text { width of Depletion layer }} $
$ =\frac{0.6 V }{6 \times 10^{-6} m }=1 \times 10^5 V / m$
$ =1 \times 10^5\, N / C$