Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. If the point (1, 4) lies inside the circle $x^2 + y^2 — 6x-10y + p = 0$ and the circle does not touch or intersect the coordinate axes, then the set of all possible values of $p$ is the interval:

JEE MainJEE Main 2014Conic Sections

Solution:

$AB=\sqrt{2^{2}+1}=\sqrt{5}$
according to question
$\sqrt{5}<\sqrt{3^{2}+5^{2}-p}< q$
$5 < 34 - p < q$
$- 29 < - P < - 25$
$29 > p > 25$

Solution Image