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Q. If the period of revolution of an artificial satellite just above the earth's surface is $T$ and the density of earth is $\rho$, then $\rho T^{2}$ :

Gravitation

Solution:

For a revolving satellite by Kepler's Third Law we use $T^{2}=\left(4 \pi^{2} / G M\right) R^{3}$ and $M=\left(4 \pi R^{3} / 3\right) \rho$ we get option $( A )$ is correct.