Q. If the parabola $y=x^2$ is tangent to the circle $x^2+(y-1)^2=c$, then the value of $c$ is equal to
Conic Sections
Solution:
Substitute $x^2=y$ to get $y+(y-1)^2=c$
or $y^2-y+1-c=0$.
$D = 1-4(1- c )=0 $
$- 3+4 c =0 $
$c = \frac{3}{4} $
