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Mathematics
If the numerically greatest term in the expansion of (1-3 x)8 for x=(1/2) is Tr then ' r ' is
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Q. If the numerically greatest term in the expansion of $(1-3 x)^8$ for $x=\frac{1}{2}$ is $T_r$ then ' $r$ ' is
Binomial Theorem
A
2
B
4
C
6
D
8
Solution:
$ \frac{T_{r+1}}{T_r}=\frac{3}{2} \gtrless 1$
$ 27 \gtrless 5 r $
$\text { for } r=5 \quad T_6 >T_5 $
$\text { for } r=6 \quad T_7< T_6$
$\therefore T_6 \text { is numerically greater }$