Question

If the melting point of ice is $ 0{}^\circ C $ and latent heat of fusion is $ 5.46\text{ }KJ\text{ }mo{{l}^{-1}}, $ the entropy change for the conversion of 18 g of ice to water at 1 atm is

• A. zero
• B. $ 20\text{ }J{{K}^{-1}} $
• C. $ 50\text{ }J{{K}^{-1}} $
• D. $ \text{360 }J{{K}^{-1}} $

Answer 1

Answer: (B)

: Here, $ \Delta {{H}_{f}}=5.46\text{ }kJ\text{ }mo{{l}^{-1}} $ $ \Delta {{S}_{f}}=\frac{\Delta {{H}_{f}}}{T}=\frac{5.46\times 1000}{273}\text{=20}\,J{{K}^{-1}} $ .