Question

If the melting point of ice is $0^°C$ and latent heat of fusion is $5.46\, kJ\, mol^{-1}$, the entropy change for the conversion of $18\, g$ of ice to water at one atmosphere is

• A. $5.46\, J \,mol^{-1}\, K^{-1}$
• B. $20\, J \,mol^{-1}\, K^{-1}$
• C. $50\, J \,mol^{-1}\, K^{-1}$
• D. $360\, J \,mol^{-1}\, K^{-1}$

Answer 1

Answer: (B)

$\Delta S_{f} =\frac{\Delta H_{f}}{T_{m.p.}}$
$=\frac{5.46\times1000}{273}$
$=20\, J \,mol^{-1}\,K^{-1}$