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Q. If the matrix $A=\begin{bmatrix}8 & -6 & 2 \\ -6 & 7 & -4 \\ 2 & -4 & \lambda\end{bmatrix}$ is singular, then $\lambda=$

Solution:

$|A|=0 \Rightarrow 20 \lambda-60=0 \Rightarrow \lambda=3$