Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. If the mass of moon is $ \frac{1}{90} $ of earths mass, its radius is $ \frac{1}{3} $ of earths radius and if $ g $ is acceleration due to gravity on earth, then the acceleration due to gravity on moon is ...... :

KEAMKEAM 2004Gravitation

Solution:

$ {{g}_{m}}=\frac{G\times M/90}{{{(R/3)}^{3}}}=\frac{1}{10}g $