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Q.
If the mass of a microscopic particle as well as its speed are halved, the de Broglie wavelength associated with the particle will
Dual Nature of Radiation and Matter
Solution:
$\lambda=\frac{h}{m v}$
$\therefore \frac{\lambda_{2}}{\lambda_{1}}=\frac{m_{1} v_{1}}{m_{2} v_{2}}$
$=\frac{2 m_{1}}{m_{1}} \frac{2 v_{1}}{v_{1}}=\frac{4}{1}$
$\therefore \lambda_{2}=4 \lambda_{1}$
New wavelength $=4 \times$ Original wavelength
$\therefore $ The wavelength increases by a factor more than $2 .$