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Q.
If the lengths of the sides of triangle are $3,5$ , and $7$ , then the largest angle of the triangle is
Trigonometric Functions
Solution:
Let $a=3, b=5, c=7$.
Then the largest angle is opposite to the longest side, i.e., $\angle C$.
Therefore, $\cos C=\frac{a^{2}+b^{2}-c^{2}}{2 a b}$
$=\frac{9+25-49}{2 \times 3 \times 5}=\frac{-1}{2}$
or $C=\frac{2 \pi}{3}$