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Physics
If the length of the filament of a heater is reduced by 10 %, the power of the heater will
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Q. If the length of the filament of a heater is reduced by $10 \%$, the power of the heater will
Current Electricity
A
increase by about $9 \%$
6%
B
increase by about $11 \%$
22%
C
decrease by about $11 \%$
56%
D
decrease by about $9 \%$
17%
Solution:
New resistance: $R'=\frac{\rho(0.9 L)}{A}=0.9 R$
$P'=\frac{V^{2}}{R'}=\frac{V^{2}}{0.9 R}=\frac{P}{0.9}$
Increase in power: $\frac{P'-P}{P} \times 100$
$=\frac{100}{9}=11 \%$