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Q. If the length of the filament of a heater is reduced by $10 \%$, the power of the heater will

Current Electricity

Solution:

New resistance: $R'=\frac{\rho(0.9 L)}{A}=0.9 R$
$P'=\frac{V^{2}}{R'}=\frac{V^{2}}{0.9 R}=\frac{P}{0.9}$
Increase in power: $\frac{P'-P}{P} \times 100$
$=\frac{100}{9}=11 \%$