Initial length of the conductor
$l_{1}=l$
Final length of the conductor
$I_{2}=2 I$
Initial cross-sectional area $A_{1}=A$
Final cross-sectional area $A_{2}=2 A$
The resistance of conductors given by
$R=\rho \frac{1}{A} \propto \frac{1}{A}$
As both the length and area are doubled
Hence, there will be no change in the resistance of the conductor and so it will remain unchanged.