1. Tardigrade
  2. Question
  3. Chemistry
  4. If the kinetic energy of a particle is reduced to half, de-Broglie wavelength becomes

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. If the kinetic energy of a particle is reduced to half, de-Broglie wavelength becomes

EAMCETEAMCET 2015

Solution:

The de-Broglie wavelength is inversely proportional to the square root of kinetic energy.
Hence, $\frac{\lambda_{1}}{\lambda_{2}}=\sqrt{\frac{( KE )_{2}}{( KE )_{1}}}$

Given that, $( KE )_{2}=\frac{1}{2}( KE )_{1}$

Then, $\frac{\lambda_{1}}{\lambda_{2}}$ or, $\lambda_{2}=\sqrt{2} \lambda_{1}$

Thus, de-Broglie wavelength becomes $\sqrt{2}$ times to the original wavelength.