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Q. If the instantaneous rate of appearance of $NO _{2}( g )$ is $0.0400\, M / s$ at some moment in time, what is the rate of disappearance of $N _{2} O _{5}( g )$ in $M / s ?$

Chemical Kinetics

Solution:

$N _{2} O _{5} \rightarrow 2 NO _{2}+\frac{1}{2} O _{2}$

$\frac{2 N _{2} O _{5}}{1}=\frac{R_{ NO _{2}}}{2}=\frac{.04}{2}=0.02$