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Q. If the imaginary part of the expression $\frac{e^{i \theta}}{z-2}+\frac{z-2}{e^{i \theta}}$ is zero, then the locus of $z$ is (where $\theta$ is a constant such that $\theta \neq \arg (z-2)$ )

Complex Numbers and Quadratic Equations

Solution:

Correct answer is (c) a circle of radius 1 and centre $(2,0)$