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Q. If the image of an object is at the focal point $ (f)$ to the light side of a convex lens, the position of the object on the left of the lens is at

TS EAMCET 2020

Solution:

The given situation is shown in the following figure
image
Given, $ v=+f, f=+f$
By $\frac{1}{v}-\frac{1}{u}=\frac{1}{f}$
We have, $\frac{1}{f}-\frac{1}{f}=\frac{1}{u} $
$\Rightarrow \frac{1}{u}=0$
$ \Rightarrow u=\infty$
So, object is at $\infty$ distance on right side of lens.