1. Tardigrade
  2. Question
  3. Chemistry
  4. If the half cell reactions are given as (i) Fe 2+(a q)+2 e- arrow Fe (s) ; E°=-0.44 V (ii) 2 H +(a q)+(1/2) O 2(g)+2 e- arrow H 2 O (l) E°=+1.23 V The E° for the reaction Fe (s)+2 H ++(1/2) O 2(g) arrow Fe 2+(a q)+ H 2 O (l) is

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Q. If the half cell reactions are given as
(i) $Fe ^{2+}(a q)+2 e^{-} \rightarrow Fe (s) ;\,\,E^{\circ}=-0.44\, V$
(ii) $2 H ^{+}(a q)+\frac{1}{2} O _{2}(g)+2 e^{-} \rightarrow H _{2} O (l)$
$E^{\circ}=+1.23\, V$
The $E^{\circ}$ for the reaction
$Fe (s)+2 H ^{+}+\frac{1}{2} O _{2}(g) \rightarrow Fe ^{2+}(a q)+ H _{2} O (l)$
is

AMUAMU 2010Electrochemistry

Solution:

$E_{\text {cell }}^{\circ} =E^{\circ}{}_{\text { cathode }}-E^{\circ}{ }_{\text {anode }}$
$=+1.23-(-0.44)$
$=+1.67\, V$