1. Tardigrade
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  3. Chemistry
  4. If the H++OH-→ H2O+13.7kcal , then heat of complete neutralisation of 1 g mole H2SO4 with a base will be:

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Q. If the $ {{H}^{+}}+O{{H}^{-}}\to {{H}_{2}}O+13.7kcal $ , then heat of complete neutralisation of $1 \,g$ mole $ {{H}_{2}}S{{O}_{4}} $ with a base will be:

Haryana PMTHaryana PMT 1999

Solution:

1 mole of $ {{H}_{2}}S{{O}_{4}} $ will be completely neutralized by two moles of $ O{{H}^{-}} $ ion producing two moles of $ {{H}_{2}}O $ . Hence, the amount of heat liberated will be $ 2\times 13.7=27.4kcal $ $ \underset{1\,mole}{\mathop{{{H}_{2}}S{{O}_{4}}}}\,+\underset{2\,moles}{\mathop{2O{{H}^{-}}}}\,\xrightarrow{{}}S{{O}_{4}}^{2-}+\underset{2\,moles}{\mathop{2{{H}_{2}}O}}\,+27.4kcal $