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Q.
If the graph of a differentiable function $ y = f(x)$ meets the lines $y = - 1$ and $y = 1$, then the graph
Application of Derivatives
Solution:
Since the function $y = f(x)$ is differentiable, and meets the line $y = - 1$ and $y = 1$
$\therefore $ the function is continuous and hence its graph meets the line $y, = 0$ at least once.