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Physics
If the Ge diode in the circuit is reverse biased, the current through 2 kΩ resistor
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Q. If the $Ge$ diode in the circuit is reverse biased, the current through $2 \,kΩ$ resistor
KEAM
KEAM 2020
A
increases by $0.2$ mA
B
decreases by $0.4$ mA
C
increases by $0.4$ mA
D
decreases by $0.25$ mA
E
does not change
Solution:
$\frac{15-0.2}{2}=\frac{14.8}{2}=7.4\, mn$
$\frac{15-0.7}{2}=7.15 \,mA$
$\therefore I_{1}-I_{2}=0.25 \,mA$