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  4. If the galvanometer current is 10 mA, resistance of the galvanometer is 40 Ω and shunt of 2 Ω is connected to the galvanometer, the maximum current which can be measured by this ammeter is

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Q. If the galvanometer current is $10\, mA$, resistance of the galvanometer is $40\, \Omega$ and shunt of $2 \, \Omega$ is connected to the galvanometer, the maximum current which can be measured by this ammeter is

Moving Charges and Magnetism

Solution:

$I=(\frac{S+G}{S})$
$(I_{g}=\frac{2+40}{2})\times 0.01$
$=0.21\, A$