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Q. If the function $f : R - {1, -1} \to A$ defined by $f(x) = \frac{x^2}{1-x^2}, $ is surjective, then $A$ is equal to

JEE MainJEE Main 2019Application of Derivatives

Solution:

$y = \frac{x^2}{1-x^2}$
Range of y : $R -[-1,0)$
for surjective function, $A$ must be same as above range.